有可能是有可能也不是，那要看买的是不是全真模拟试卷？
函授教学主要以有计划、有组织、有指导的自学为主，并组织系统的集中面授，参加函授学习的学生平时以自学为主，面授时间一般为周末或者晚上集中面授7-10天左右，下学期开学后考试。那么，有专升本函授考试高等数学试题及答案吗？ 2023年成人高考专升本《高等数学二》模拟试卷及参考答案一 2023年成人高考专升本《高等数学二》模拟试卷及参考答案汇总 2023年成人高考专升本《高等数学二》模拟试卷及参考答案一 2023年成人高考专升本《高等数学二》模拟试卷及参考答案二 2023年成人高考专升本《高等数学二》模拟试卷及参考答案三 2023年成人高考专升本《高等数学二》模拟试卷及参考答案四 2023年成人高考专升本《高等数学二》模拟试卷及参考答案五自考/成考有疑问、不知道如何总结自考/成考考点内容、不清楚自考/成考报名当地政策，点击底部咨询官网，免费领取复习资料：
初二数学是一个至关重要的学年,同学们一定要在数学期末模拟考试中仔细审题和答题。以下是我为你整理的初二数学上册期末模拟试卷，希望对大家有帮助!
一、细心选一选(本题共10小题，每小题3分，共30分)
【请将精心选一选的选项选入下列方框中，错选，不选，多选，皆不得分】
1、点(-1，2)位于( )
(A)第一象限 (B)第二象限 (C)第三象限 (D)第四象限
2、若∠1和∠3是同旁内角，∠1=78度，那么下列说法正确的是( )
(A)∠3=78度 (B) ∠3=102度 (C)∠1+∠3=180度(D)∠3的度数无法确定
3.如图，已知∠1=∠2，则下列结论一定正确的是( )
(A)∠3=∠4 (B) ∠1=∠3 (C) AB//CD (D) AD//BC
4.小明、小强、小刚家在如图所示的点A、B、C三个地方，它们的连线恰好构成一个直角三角形，B，C之间的距离为5km，新华书店恰好位于斜边BC的中点D，则新华书店D与小明家A的距离是( )
(A)2.5km (B)3km (C)4 km (D)5km
5.下列能断定△ABC为等腰三角形的是( )
(A)∠A=30º、∠B=60º (B)∠A=50º、∠B=80º
(C)AB=AC=2，BC=4 (D)AB=3、BC=7，周长为13
6.某游客为爬上3千米的山顶看日出，先用1小时爬了2千米，休息0.5小时后，用1小时爬上山顶。山高h与游客爬山所用时间t之间的函数关系大致图形表示是( )
7. 下列不等式一定成立的是( )
(A)4a>3a (B)3-x<4-x (C)-a>-3a (D)4a>3a
8.如图，长方形ABCD恰好可分成7个形状大小相同的小长方形，如果小长方形的面积是3，则长方形ABCD的周长是( )
(A)17 (B)18 (C)19 (D)
9. 一次函数y=x图象向下平移2个单位长度再向右平移3个单位长度后，对应函数关系式是( )
(A)y=2x -8 (B)y=12x (C)y=x+2 (D)y=x-5
10.在直线L上依次摆放着七个正方形，已知斜放置的三个正方形的面积分别为1、2、3，正放置的四个正方形的面积依次是S1、S2、S3、S4，则S1+2S2+2S3+S4=( )
(A)5 (B)4 (C) 6 (D)、10
二、精心填一填(每小题3分，共24分)
11.点P(3，-2)关于y轴对称的点的坐标为 .
12.已知等腰三角形的两边长分别为3和5，则它的周长是 .
13.在Rt△ABC中，CD、CF是AB边上的高线与中线，若AC=4，BC=3 ，则CF= ;CD= .
14.已知等腰三角形一腰上的中线将它周长分成9cm和6cm 两部分，则这个等腰三角形的底边长是__
15.一次函数y=kx+b满足2k+b= -1，则它的图象必经过一定点，这定点的坐标是 .
16.已知坐标原点O和点A(1，1)，试在X轴上找到一点P，使△AOP为等腰三角形，写出满足条件的点P的坐标__
17.如图，△ABC中，∠C=90°，AB的中垂线DE交AB于E，交BC于D，若AB=10，AC=6，则△ABC的周长为 .
18. 如图，有八个全等的直角三角形拼成一个大四边形ABCD和中间一个小四边形MNPQ，连接EF、GH得到四边形EFGH，设S四边形ABCD=S1，S四边形EFGH=S2，S四边形MNPQ=S3，若S1+S2+S3，则S2= .
三、仔细画一画(6分)
19.(1)已知线段a,h,用直尺和圆规作等腰三角形ABC,底边BC=a,BC边上的高为h
└─────┘a └──────┘h
(2)如图，已知△ABC，请作出△ABC关于X轴对称的图形.并写出A、B、C 关于X轴对称的点坐标。
四、用心做一做(40分)
20.(本题6分)解下列不等式(组)，并将其解集在数轴上表示出来。
(1)x+16 <5-x4 +1 (2) 2x>x+2;①
x+8>x-1;②
21.(本题5分)如图，已知AD∥BC，∠1=∠2，说明∠3+∠4=180°，请完成说明过程，并在括号内填上相应依据：
解：∠3+∠4=180°，理由如下：
∵AD∥BC(已知)，
∴∠1=∠3( )
∵∠1=∠2(已知)
∴∠2=∠3(等量代换);
∴ ∥ ( )
∴∠3+∠4=180°( )
22.(本题5分)如图，在△ABC中，点D、E在边BC上，且AB=AC，AD=AE，请说明BE=CD的理由.
23.(本题6分)某软件公司开发出一种图书管理软件，前期投入的各种费用总共50000元，之后每售出一套软件，软件公司还需支付安装调试费用200元，设销售套数x(套)。
(1)试写出总费用y(元)与销售套数x(套)之间的函数关系式.
(2)该公司计划以400元每套的价格进行销售，并且公司仍要负责安装调试，试问：软件公司售出多少套软件时，收入超出总费用?
24.(本题8分)“十一黄金周”的某一天，小刚全家上午8时自驾小汽车从家里出发，到距离180千米的某著名旅游景点游玩，该小汽车离家的路程S(千米)与时间t (时)的关系可以用右图的折线表示。根据图象提供的有关信息，解答下列问题：
(1)小刚全家在旅游景点游玩了多少小时?
(2)求出整个旅程中S(千米)与时间t (时)的函数关系式，并求出相应自变量t的取值范围。
(3)小刚全家在什么时候离家120㎞?什么时候到家?
25.(本题10分)如图，已知直线y=﹣34 x+3与x轴、y轴分别交于点A、B，线段AB为直角边在第一象限内作等腰Rt△ABC，∠BAC=90°.
(1)求△AOB的面积;
(2)求点C坐标;
(3)点P是x轴上的一个动点，设P(x,0)
①请用x的代数式表示PB2、PC2;
②是否存在这样的点P，使得|PC-PB|的值最大?如果不存在，请说明理由;
如果存在，请求出点P的坐标.
一、细心选一选(本题共10小题，每小题3分，共30分)
【请将精心选一选的选项选入下列方框中，错选，不选，多选，皆不得分】
题号 1 2 3 4 5 6 7 8 9 10
答案 B D D A B D B C D C
X k B 1 . c o m
二、精心填一填(每小题3分，共24分)
11. (-3，-2) 12. 11或3
13 2.5 , 2.4 14 3或7
15 (2，-1) 16 (1,0) (2,0) (2 ,0) (- ,0)
17 14 18 203
三、仔细画一画(6分)
19.(1)图形略 图形画正确得2分,结论得1分.
(2)解:A1 (2 ,-3) B1(1 ,-1) C1(3 ,2)…………得2分 画出图形得 1分
四、用心做一做(40分)
20.(本题6分)(1)解：去分母，得2(x+1)<3(5-x)+12
去括号移项，得2x+3x<15+12-2
合并同类项，得5x<25
方程两边都除5，得x<5
∴原不等式的解集为x<5如图所示：
(2)解：由①得，x>2
由②得，x<3
∴原不等式的解集为2
21.(本题5分)解：∠3+∠4=180°，理由如下：
∵AD∥BC(已知)，
∴∠1=∠3(两直线平行，内错角相等);
∵∠1=∠2(已知)
∴∠2=∠3(等量代换);
∴EB∥DF(同位角相等，两直线平行)
∴∠3+∠4=180°(两直线平行，同胖内角互补)
w W w .x K b 1.c o M
22.(本题5分)解：∵AB=AC，AD=AE
∴∠ABC=∠ACB，∠ADC=∠AEB(等角对等边)
又∵在△ABE和△ACD中，
∠ABC=∠ACB(已证)
∠ADC=∠AEB(已证)
AB=AC(已知)
∴△ABE≌△ACD(AAS)
∴BE=CD(全等三角形的对应边相等)
23.(本题6分)
解(1)：设总费用y(元)与销售套数x(套)，
根据题意得到函数关系式：y=50000+200x.
解(2)：设软件公司至少要售出x套软件才能确保不亏本，
则有：400x≥50000+200x 解得：x≥250
答：软件公司至少要售出250套软件才能确保不亏本.
24.(本题8分)
解: (1)4小时
(2)①当 8≤t≤10 时，
设s=kt+b 过点(8，0)，(10，180) 得 s=90t-720
②当10≤t≤14 时，得s=180
③当14≤t时 过点 (14，180)，(15，120)
∴ s=90t-720(8≤t≤10) s=180(10≤t≤14) s= -60t +1020(14≤t)
(3)①当s=120 km时，90t-720=120 得 t=9 即 9时20分
-60t+1020=120 得 t=15
②当s=0时 -60t+1020=0 得 t=17
答：9时20分或15时离家120㎞，17时到家。
25.(本题10分)
(1)由直线y=- x +3，令y=0，得OA=x=4，令x=0，得OB=y=3，
(2)过C点作CD⊥x轴，垂足为D，
∵∠BAO+∠CAD=90°，∠ACD+∠CAD=90°，
∴∠BAO=∠ACD，
又∵AB=AC，∠AOB=∠CDA=90°，
∴△OAB≌△DCA，
∴CD=OA=4，AD=OB=3，则OD=4+3=7，
∴C(7，4);
(3)①由(2)可知，PD=7-x，
在Rt△OPB中，PB2=OP2+OB2=x2+9，
Rt△PCD中，PC2=PD2+CD2=(7-x)2+16=x2-14x+65，
②存在这样的P点.
设B点关于 x轴对称的点为B′，则B′(0，-3)，
连接CB′，设直线B′C解析式为y=kx+b，将B′、C两点坐标代入，得
b=-3;
7k+b=4;
k=1
解得 b=-3
所以，直线B′C解析式为y=x-3，
令y=0，得P(3，0)，此时|PC-PB|的值最大，
故答案为：(3，0).
只含x、z而缺y的方程G(x，z)=0表示母线平行于y轴的柱面，如Z=x²
恩，365和华夏大地上都有
有可能是有可能也不是，那要看买的是不是全真模拟试卷？
小升初系列综合模拟试卷（一） 一、填空题：3．一个两位数，其十位与个位上的数字交换以后，所得的两位数比原来小27，则满足条件的两位数共有（ ）个． 5.图中空白部分占正方形面积的______分之______.6．甲、乙两条船，在同一条河上相距210千米．若两船相向而行，则2小时相遇；若同向而行，则14小时甲赶上乙，则甲船的速度为______． 7．将11至17这七个数字，填入图中的○内，使每条线上的三个数的和相等． 8．甲、乙、丙三人，平均体重60千克，甲与乙的平均体重比丙的体重多3千克，甲比丙重3千克，则乙的体重为______千克． 9．有一个数，除以3的余数是2，除以4的余数是1，则这个数除以12的余数是______． 10．现有七枚硬币均正面（有面值的面）朝上排成一列，若每次翻动其中的六枚，能否经过若干次的翻动，使七枚硬币的反面朝上______（填能或不能）． 二、解答题： 1．浓度为70％的酒精溶液500克与浓度为50％的酒精溶液300克，混合后所得到的酒精溶液的浓度是多少？2．数一数图中共有三角形多少个？3．一个四位数，它的第一个数字等于这个数中数字0的个数，第二个数字表示这个数中数字1的个数，第三个数字表示这个数中数字2的个数，第四个数字等于这个数中数字3的个数，求出这个四位数．小升初系列综合模拟试卷（一）答案 一、填空题：3：设原两位数为10a+b，则交换个位与十位以后，新两位数为10b+a，两者之差为（10a+b）-（10b+a）=9（a-b）=27，即a-b=3，a、b为一位自然数，即96，85，74，63，52，41满足条件.共6个4： 5：把原图中靠左边的半圆换成面积与它相等的右半部的半圆，得右图，图 6：两船相向而行，2小时相遇．两船速度和210÷2=105（千米/时）；两船同向行，14小时甲赶上乙，所以甲船速-乙船速=210÷14=15（千米/时），由和差问题可得甲：（105+15）÷2=60（千米/时）．乙：60-15=45（千米/时）． 7：11+12+13+14+15+16+17=98．若中心圈内的数用a表示，因三条线的总和中每个数字出现一次，只有a多用3两次，所以98+2a应是3的倍数，a=11，12，…，17代到98+2a中去试，得到a=11，14，17时，98+2a是3的倍数． （1）当a=11时98+2a=120，120÷3=40 （2）当a=14时98+2a=126，126÷3=42 （3）当a=17时98+2a=132，132÷3=44 8：甲、乙的平均体重比丙的体重多3千克，即甲与乙的体重比两个丙的体重多3×2=6（千克），已知甲比丙重3千克，得乙比丙多6-3=3千克．又丙的体重+差的平均=三人的平均体重，所以丙的体重=60-（3×2）÷3=58（千克），乙的体重=58+3=61（千克）． 9：满足条件的最小整数是5，然后，累加3与4的最小公倍数，就得所有满足这个条件的整数，5，17，29，41，…，这一列数中的任何两个的差都是12的倍数，所以它们除以12的余数都相等即都等于5．10：若使七枚硬币全部反面朝上，七枚硬币被翻动的次数总和应为七个奇数之和，但是又由每次翻动七枚中的六枚硬币，所以无论经过多少次翻动，次数总和仍为若干个偶数之和，所以题目中的要求无法实现。 二、解答题：1：混合后酒精溶液重量为：500+300=800（克），混合后纯酒精的含量：500×70％+300×50％=350+150=500（克），混合液浓度为：500÷800=0.625=62.5％．2：（1）首先观察里面的长方形，如图1，最小的三角形有8个，由二个小三角形组成的有4个；由四个小三角形组成的三角形有4个，所以最里面的长方形中共有16个三角形．（2）把里面的长方形扩展为图2，扩展部分用虚线添出，新增三角形中，最小的三角形有8个：由二个小三角形组成的三角形有4个；由四个小三角形组成的三角形有4个；由八个小三角形组成的三角形有4个，所以新增28个．由（1）、（2）知，图中共有三角形：16+28=44（个）． 3：由四位数中数字0的个数与位置入手进行分析，由最高位非0，所以至少有一个数字0．若有三个数字0，第一个数字为3，则四位数的末尾一位非零，这样数字个数超过四个了．所以零的个数不能超过2个．（1）只有一个0，则首位是1，第2位不能是0，也不能是1，；若为2，就须再有一个1，这时由于已经有了2，第3个数字为1，末位是0；第二个数大于2的数字不可能．（2）恰有2个0，第一位只能是2，并且第三个数字不能是0，所以二、四位两个0，现在看第三个数字，由于第二个和第四个数字是0，所以它不能是1和3，更不能是3以上的数字，只能是2．（1210和2020） 4：即0.2392…＜原式＜0.2397…． （0.239）小升初系列综合模拟试卷（二） 一、填空题： 1．用简便方法计算：2．某工厂，三月比二月产量高20％，二月比一月产量高20％，则三月比一月高______％．3．算式： （121+122+…+170）-（41+42+…+98）的结果是______（填奇数或偶数）． 4．两个桶里共盛水40斤，若把第一桶里的水倒7斤到第2个桶里，两个桶里的水就一样多，则第一桶有______斤水． 5．20名乒乓球运动员参加单打比赛，两两配对进行淘汰赛，要决出冠军，一共要比赛______场． 6．一个六位数的各位数字都不相同，最左一位数字是3，且它能被11整除，这样的六位数中最小的是______． 7．一个周长为20厘米的大圆内有许多小圆，这些小圆的圆心都在大圆的一个直径上．则小圆的周长之和为______厘米． 8．某次数学竞赛，试题共有10道，每做对一题得8分，每做错一题倒扣5分．小宇最终得41分，他做对______题． 9．在下面16个6之间添上+、-、×、÷（），使下面的算式成立： 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6=1997 二、解答题： 1．如图中，三角形的个数有多少？ 2．某次大会安排代表住宿，若每间2人，则有12人没有床位；若每间3人，则多出2个空床位．问宿舍共有几间？代表共有几人？ 3．现有10吨货物，分装在若干箱内，每箱不超过一吨，现调来若干货车，每车至多装3吨，问至少派出几辆车才能保证一次运走？ 4．在九个连续的自然数中，至多有多少个质数？ 小升初系列综合模拟试卷（二）答案 一、填空题： 1．（1/5） 2．（44）〔1×（1+20％）×（1+20％）-1〕÷1×100％=44％ 3．（偶数）在121+122+…+170中共有奇数（170+1-121）÷2=25（个），所以121+122+…+170是25个奇数之和再加上一些偶数，其和为奇数，同理可求出在41+42+…+98中共有奇数29个，其和为奇数，所以奇数减奇数，其差为偶数． 4．（27） （40+7×2）÷2=27（斤） 5．（19） 淘汰赛每赛一场就要淘汰运动员一名，而且只能淘汰一名．即淘汰掉多少名运动员就恰好进行了多少场比赛．即20名运动员要赛19场． 6．（301246） 设这六位数是301240+a（a是个一位数），则301240+a=27385×11+（5+a），这个数能被11整除，易知a=6． 7．（20） 每个小圆的半径未知，但所有小圆直径加起来正好是大圆的直径。所以所有小圆的周长之和等于大圆周长，即20厘米． 8．（7） 假设小宇做对10题，最终得分10×8=80分，比实际得分41分多80-41=39．这多得的39分，是把其中做错的题换成做对的题而得到的．故做错题39÷（5+8）=3，做对的题10-3=7． 9．（6666÷6+666+6×6×6+6-6÷6-6÷6=1997）． 先用算式中前面一些6凑出一个比较接近1997的数，如6666÷6+666=1777，还差220，而6×6×6=216，这样6666÷6+666+6×6×6=1993，需用余下的5个6出现4：6-6÷6-6÷6=4，问题得以解决．10．（110）二、解答题 1．（22个） 根据图形特点把图中三角形分类，即一个面积的三角形，还有一类是四个面积的三角形，顶点朝上的有3个，由对称性知：顶点朝下的也有3个，故图中共有三角形个数为16+3+3=22个． 2．（14间，40人） （12+2）÷（3-2）=14（间） 14×2+12=40（人） 3.4．（4个） 这个问题依据两个事实： （1）除2之外，偶数都是合数； （2）九个连续自然数中，一定含有5的倍数．以下分两种情况讨论：①九个连续自然数中最小的大于5，这时其中至多有5个奇数，而这5个奇数中一定有一个是5的倍数，即其中质数的个数不超过4个，②九个连续的自然数中最小的数不超过5，有下面几种情况： 1，2，3，4，5，6，7，8，9 2，3，4，5，6，7，8，9，10 3，4，5，6，7，8，9。10，11 4，5，6，7，8，9，10，11，12， 5，6，7，8，9，10，11，12，13 这几种情况中，其中质数个数均不超过4． 综上所述，在九个连续自然数中，至多有4个质数．
有可能是有可能也不是，那要看买的是不是全真模拟试卷？
第一题：
第二题：
第三题：
第四题：
第五题：
这部分内容主要考察的是函数解析式的知识点：
两个变量A与B之间，如果A随着B的每个值，都有唯一确定的值与之对应，那么A就是B的函数。从对应角度理解，有两种形式：
1、一对一，就是一个B值对应一个A值，反之，一个A值也对应一个B值（当然，此时B也是A的函数）。
2、一对多，就是多个B值对应一个A值。（此时一个A值对应多个B值，所以B不是A的函数）。
函数主要有三种表达方式：列表；图象；解析式（较常用）。因此函数解析式只是函数的一种表达方式。
由于自变量范围不同，所以是不同的两个函数。有时，函数书写过程中，存在省略自变量范围的形式：如：y=2x-5；(4) y=√2x-5；（5）y=1/(2x-5)，这时它们的自变量范围就是使表达式有意义的自变量的值。的自变量范围是：x为任意实数（注：这个概念我们默认在实数范围内讨论，下同）；的自变量范围是：x>=2.5；的自变量范围是：x≠2.5。
你们这样是要出事的
全国06年4月自学考试：英语（二）试卷及答案 2006年09月21日 14:18 来源：腾讯教育 第 1 2 3 4 5 6 页 PART ONE （50 POINTS） I.Vocabulary and Structure （10 points， 1point each） 1. It would be better to make a decision now， ______ leave it until next week. A. other than B. rather than C. less than D. more than 2. We‘ll inform you as soon as tickets become ______. A. valuable B. capable C. acceptable D. available 3. The foreign company has been______ running this factory for decades. A. enormously B. effectively C. infinitely D. extremely 4. If you ______ my advice， you wouldn‘t be in such trouble now. A. took B. takes C. has taken D. had taken · 免费用QQ打电话超清晰 · 银行卡 安全快捷换Q币 · 沟通无极限手机Q时代 · 魔法表情秀出百变心情 · 管中窥豹 明察秋毫 · QQ秀 秀出个性真自我 5. The meeting ______， we left the room quickly for dinner. A. over B. was over C. is over D. been over 6. All the money ______， Frederick started looking for work. A. having spent B. has been spent C. having been spent D. had been spent 7. ______ his talk when Mary ran out of the lecture hall. A. Hardly had be begun B. Hardly he had begun C. Hardly he has begun D. He hardly had begun 8. The two sisters are _____ in many ways， not only in appearance but also in temperament. A. like B. likely C. alike D. lively 9. The purpose of the program is to provide training for employees so that they can work ______. A. late B. later C. lately D. latest 10. I hope my boy friend will be handsome， strong and ______ kind. A. above all B. in all C. at all D. after all II. Cloze Test （10 points， 1 point each） However careful one may be， he cannot possibly listen carefully to everything that he hears. There are 11 of reasons for this. One of them is the overload of messages most of us 12 each day. In addition to the numerous hours we 13 hearing other people speak， we may spend several hours listening to the radio or sitting in front of a television set. 14， it is impossible to focus our attention completely on what is said； our mind might be 15 elsewhere. Preoccupation with our personal concerns is 16 reason we don‘t always listen carefully. A romance 17 sour or a good grade on a test may take prominence in our mind even as 18 is speaking to us. Furthermore， we are surrounded by all kinds of noises which interfere 19 listening. For example， voices at a party or 20 of traffic may simply make it difficult for us to catch everything that is being said. 11. A. the number B. a number C. number D. numbers 12. A. accept B. obtain C. receive D. possess 13. A. put B. consume C. spend D. spare 14. A. Besides B. Whereas C. Otherwise D. Nevertheless 15. A. wondering B. swinging C. recycling D. wandering 16. A. other B. some C. the other D. another 17. A. gone B. going C. goes D. went 18. A. anyone B. everyone C. someone D. few 19. A. to B. with C. of D. about 20. A. sound B. noise C. voice D. scream III. Reading Comprehension （30 points， 2 points each） Passage One Questions 21 to 25 are based on the following passage. Many of today‘s most trusted sales techniques were invented over a century ago by a young merchant named Eaton in Toronto. When he was young， Eaton worked briefly with his brothers in small-town stores. In 1869， he sep up his own shop in downtown Toronto. He had many competitors， but he was also ambitious and had a plan for success. He offered a unique style of trade， but as was expected， all the other shopkeepers laughed at him， believing he would eventually fail. However， Eaton was not a man to be easily defeated； he came up with a brand new notion of business – “Goods satisfactory， or money refunded.” He sold all his goods at fixed prices and only for cash. With a sharp sense of what the public wanted， he went out of the way to meet their needs. His business grew rapidly. He set up new branches and started mail order service that allowed people to buy from a list of his goods. Eaton‘s list—advertisements of his day—was the first of its kind. It was distributed and read all over the country. It was the only way to access good-quality goods at reasonable prices for people living far away from big cites. It became part of their life. They even called it The Wishing Book. The secret of the list’s success was that Eaton gained the respect of this customers； they trusted him for good prices and quality goods. Probably because he remembered his miserable early days in Ireland， Eaton thought much of the welfare of his employees： better working conditions， shorter weekday hours than his competitors and Saturday afternoons off in the summer. In all this， he was a leader. 21. The best description of Eaton is that ______. A. he was the richest merchant in Toronto B. he was a successful technical inventor C. he introduced new sales practices D. he changed people‘s ideas about businessmen 22. Eaton‘s success lay primarily in that ____. A. he sold only good quality goods B. he was the first person to provide good service C. he treated his employees better than any of his competitors D. he won respect from his customers 23. From the passage we can infer that ______. A. Eaton invented the idea of the internet shopping B. Eaton drove other businessmen to failure C. Eaton never sold his goods on credit D. Eaton was defeated by his rivals 24. The best title for this passage is _____. A. Good Goods， of Money Refunded B. Eaton， a Sales Inventor C. Customers‘ Respect， a Secret of Success D. Eaton‘s list， a Welcome Event in Sales History 25. Eaton‘s List was important to people on farms because it was a convenient way of getting _____. A. good-quality goods at reasonable prices B. goods at unreasonable prices C. good-quality goods at unreasonable prices D. poor-quality goods at reasonable prices Passage Two Questions 26 to 30 are based on the following passage. The threat of a global outbreak （疾病大爆发） of bird flu makes it urgent for the international community to cooperate effectively. Wealthy countries will have to provide hundreds of millions of dollars for the testing and production of medicines necessary for treating patients suffering from bird flu. Developing countries， particularly in Southeast Asia， where the bird flu virus （病毒） has spread since 1997， must work out special programs so that farmers will not hide sighs of possible outbreaks. In addition， the way such farm birds as chickens and ducks are traditionally raised and marketed in the developing world should be changed； there should be more distance between the birds and their keepers. Countries should deal with the disease with joint effort. If one country is inadequately prepared， it will be a threat to every other country. The potential effects of a national outbreak of bird flu are enormous. Firstly， an outbreak may kill large numbers of people. World Health Organization （WHO） estimates that an outbreak similar to the mild Hong Kong flu of 1968 could kill as many as 7.4 millions people. If it were as dangerous as the 1918 Spanish flu， which killed 50 million， the number would be much higher. Secondly， such an outbreak may cause great financial damage. The latest outbreak of bird flu， which began in December 2003， has cost Southeast Asia more than $10 billion and depressed its GDP by 1.5 percent. If a new outbreak of bird flu were to last for a whole year， $800 billion would be lost. Despite the 124 human cases and 63 deaths from bird flu since December 2003， the virus remains mainly a disease animals. However， the more animals that die of the disease， the more chances it has of spreading to people. Large numbers of dead or dying birds mean that more people will be exposed to the virus and change into a virus with new characteristics. If the international community works together efficiently， man can surely prevent such a virus and possibly save millions of lives. 26. Faced with the threat of a global outbreak of bird flu， the international community should ________. A. establish new markets B. work together effectively C. stop birds from flying to other countries D. raise fewer chickens and ducks 27. The second paragraph focuses on ______. A. World Health Organization B. flus in Hong Kong and Spain C. the economy of Southeast Asia D. possible effects of a bird flu outbreak 28. The number of people who have died of bird flu since 2003 is _______. A. 63 B. 124 C. 7.4 million D. 50 million 29. In the third paragraph， the author is mainly interested in _____. A. stimulating financial growth B. reducing economic damages C. saving human lives D. protecting bird species 30. The passage deals with all the following aspects bird flu EXCEPT _______. A. the origin and history of bird flu B. the importance of international cooperation C. the possible dangers of a national outbreak D. the significance of preventing it from spreading Passage Three Questions 31 to 35 are based on the following passage. The long summer holidays are finally over and some parents are pleased. “We worry more about their safety in the holidays，” explains one mother from North London. If teenagers are not wandering around on public transport in a big and potentially dangerous city， they are chatting to strangers in an internet chat room！ Well， that‘s an extreme picture of the UK today， but many parents are worried about how much freedom they can give their children during the holidays and at weekends. Weekends are not the only time to worry！ Newspaper are full of stories about too many school kids going to school by car because their parents do not want them to travel alone on a bus or train. This summer there were more frightening stories of teenagers disappearing with questionable friends that they met on the net. All the Media stories help increase parents fears， but is the UK really so dangerous？ Many young people feel that life for their parents was easier. In the 1960s young people played in the streets more and traveled around town without their parents. “At least our parents can keep tabs on us，” says 16-year-old Julia. “So many people have mobile phones now and their parents ring to find out where they are. I use my mobile to get Dad to come to the station when I arrive late.” Mobiles are not just expensive toys； they help keep young people safe. Most significantly， they help keep young people safe. Most significantly， they make parents feel better. Only one problem is， though， that some young people have been attacked by thieves who want to steal their mobile phones. Young people like going out with friends， but they now need to learn how to get home safely. Five million young people in the UK between the ages of 9 to 16 use chat rooms to make friends， but they， too， need to be careful and never give their personal details to a stranger. Young people today have more opportunities to meet new people and go out at night more than their parents ever did. Now school， television programs and newspapers must help teenagers to enjoy their freedom and to be responsible for their own safety. 31. Some parents are upset about the summer holidays mainly because their children ______. A. wander around on bus in the city B. chat to strangers in Internet chat rooms C. make questionable friends on the net D. are taken little care of by teachers 32. For the sake of the safety， many parents send their kids to school ________. A. by car B. by bus C. by train D. by public transport 33. Most significantly， mobile phones _______. A. enable parents keep a close watch on their kids B. help keep teenagers safe C. make parents feel less worried D. protect teenagers from being attacked 34. Teenagers should never give any strangers ______. A. their mobile phone numbers B. their family address C. their personal information D. their parents‘ names 35. This passage is mainly about ________. A. freedom for teenagers in summer holidays B. safety for teenagers in summer holidays C. activities for teenagers in summer holidays D. troubles for teenagers in summer holidays PART TWO （50 POINTS） IV. Word Spelling （10 points， 1 point for two items） 将下列汉语单词译成英语。每个单词的词类、首字母及字母数目均已给出。请将完整的单词写在答题纸上。 36. 获胜者，优胜者 n. w_ _ _ _ _ 37. （使）枯萎，凋谢 v. w_ _ _ _ _ 38. 垂直的，竖的 a. v_ _ _ _ _ _ _ 39. 易变的，变量的 a. v_ _ _ _ _ _ _ 40. 唯一的，独特的 a. u_ _ _ _ _ 41. 地下的，隐蔽的 a. u_ _ _ _ _ _ _ _ _ _ 42. 真实的，如实地 ad. t_ _ _ _ _ _ _ _ _ 43. 星期二 n. T_ _ _ _ _ _ 44. 传统，惯例 n. t_ _ _ _ _ _ _ _ 45. 同情，同情心 n. s_ _ _ _ _ _ _ 46. 投降，让步 vi. s_ _ _ _ _ _ _ _ 47. 足够的，充分的 a. s_ _ _ _ _ _ _ _ _ 48. 亲属，亲戚 n. r_ _ _ _ _ _ _ 49. 抵抗，反抗 n. r_ _ _ _ _ _ _ _ _ 50. 有目的的，蓄意的 a. p_ _ _ _ _ _ _ _ _ 51. 财产；性质 n. p_ _ _ _ _ _ _ 52. 俯望，漏看 vt. o_ _ _ _ _ _ _ 53. 发源，源自 vi. o_ _ _ _ _ _ _ _ 54. 音乐的，悦耳的 a. m_ _ _ _ _ _ 55. 意图，打算 n. i_ _ _ _ _ _ _ _ V. Word Form （10 points， 1 point each） 将括号中的各词变为适当的形式填入空白。答案写在答题纸上。 56.He _________（write） her 10 letters since he met her last years. 57. I think it necessary for him ________ （finish） the work in time. 58. The house is ______ （complete） before his brother‘s wedding ceremony. 59. You had better ________ （bring） enough money with you. 60. The _______ （good） he feels， the more work he will do. 61. If I hadn‘t listened to you， I would _______ （make） such a silly mistake. 62. The three players repeatedly denied ________ （take） any drug. 63. People who are entitled to ________ （vote） should be over eighteen. 64. The government has taken measures to reduce the total energy ______（consume）。 65. If she ______（catch） the 10 O‘clock train， she can get there by lunch time. VI. Translation from Chinese into English （15 points， 3 points each） 将下列各句译成英语并将答案写在答题纸上。 66. 男人的平均身高比女人高几英寸。 67. 你所说的与我们正在讨论的豪不相干。 68. 教育应该使每个学生德、智、体全面发展。 69.这本书对读者产生了很大影响。 70.这次考试比我们预想的要难得多。 VII. Translation from English into Chinese （15 points） 将下列短文译成汉语并将答案写在答题纸上。 There is a clear distinction between one who is supposed to know and another， usually a younger person who is supposed not to know. However， teaching is not necessarily the area of a special group of people， nor should it be looked upon as a technical skill. Teaching can be more like guiding and assisting than forcing information into a blank mind. If you have a certain skill， you should be able to share it with others. You do not have to get a certificate to convey what you know to them or to help them in their attempt to teach themselves. All of us， from the very youngest children to the oldest members of our society， should come to realize our own talent and abilities as teachers. We can share what we know， however little it might be， with others who have need of that knowledge or skill. 「答案及评分参考」 I. Vocabulary and Structure （本大题共10小题，每小题1分，共10分） 1.B 2.D 3.B 4.D 5.A 6.C 7.A 8.C 9.B 10.A II. Cloze Test （本大题共10小题，每小题1分，共10分） 11.B 12.C 13.C 14.A 15.D 16.D 17.A 18.C 19.B 20.B III. Reading Comprehension （本大题共15小题，每小题2分，共30分） 21.C 22.D 23.C 24.B 25.A 26.B 27.D 28.A 29.C 30.A 31.D 32.A 33.C 34.C 35.B IV. Word Spelling （本大题共20小题，每两小题1分，共10分） 36. winner 37. wither 38. vertical 39. variable 40. unique 41. underground 42. truthfully 43.Tuesday 44. tradition 45. sympathy 46. surrender 47. sufficient 48. relative 49. resistance 50. purposeful 51. property 52. overlook 53. originate 54. musical 55. intention [评分参考] 多写、少写或错写一个或一个以上的字母均为错 V. Word From （本大题共10小题，每小题1分，共10分） 56. has written 57. to finish 58. to be completed 59. bring 60. better 61. have made 62. taking 63. vote 64. consumption 65. catches [评分参考] 语法错误或拼写错误均不给分。 VI. Translation from Chinese into English （本大题共5小题，每小题3分，共15分） 66. On the average， men are higher than women by several inches/several inches higher than women. 67. What you said has nothing to do/has no relevance with what we are discussing. 68. Education should enable every student to develop morally，intellectually and physically. 69. The book has made a great impact/had a great effect/influence on its readers. 70. The test was much more difficult than we had expected.
答案？这个社会真受不了。。。有答案还去考什么？？干嘛不直接给一个文凭？？？
英语二（每个人都自己改几道选择题，大题呀不要都一样了）一单选1、 Elderly ……A2、 It is ……A3、 Unexpectedly ……C4、 A good manager ……C5、 Everything ……C6、 Besides ……B7、 The biologist ……B8、 Scientists ……A9、 ——，jane is ……D10、——I admire ……D二、完型 Courage is an essential attribute in、learning a foreign language。……11-----20 DABCB, ABDCB三、阅读段落一 Karen was 14，depressed and not doing well at school。……21------25 CDBDD段落二 the amount of time kids spend online is a source of frustration for many parents。……26------30 AABCD段落三 American scientist have found that some birds are more intelligent than believed。……31-----35 AAABD四、单词翻译36、古代的、古老的ancient37、生涯、经历career38、毁坏、损伤damage39、特别、尤其especially40、渐渐的、逐步的gradually41、车库garage42、诚实的、正直的honesta43、保险、保险金insurance44、汁、液juice45、商人merchant46、谈判、协商negotiate47、发生、出现occur48、停止、放弃quit49、包围、环绕surround50、薪金、薪水salary51、治疗、对待treatment52、技术、技巧technique53、美德virtue54、值得做的worth55、屈服、屈从yield五、变换格式56、（become）become57、（curious）curiosityaa58、（watch）watching59、（be）is60、（expect）expectation61、（agree）agreeable62、（crowd）crowded63、（rich）Enrich64、(praise) has been praised65、(appear) appeared五、翻译66、我们都被大自然的美深深的吸引住了we are deeply impressed with the beauty of nature67、如果想省钱，你就不要买那块昂贵的表。If you want to save money ,do not buy the expensive watch68、那篇小说是她创作时心情的真实反映。The novel really reflects his mood when he wrote it69、应歌迷要求，年轻歌手又唱了一首民歌。The young singer sang a folk song again at the fans request70、一些科学家认为需要有更多的数据才能证明这一事实。Some scientists believe that more data car prove the reality.六、翻译短文每种文化都有自已的理想行为，美国也不例外。在那里，孩子们被鼓励要开放、直接。美国人认为开放是诚实的表现，他们对于沉默和保守提出怀疑。他们觉得你一定在隐藏什么如果你没说出来。他们觉得由于沉默而受威胁，这一点他们不相信也不理解。然而，许多其它文化并不看重开放和直接。事实上，他们不喜欢这些品质因为对它们而言，开放和直接孩子好像很粗鲁。在它信眼里不像成人的行为。那么并不令人吃惊的是许多种文化的误解也由于开放和直接所致
考试辅导频道检索。
专家编写·紧扣大纲·命中率高！本系列试卷由北大、清华、人大等名校百名命题专家，根据最新教材及最新《自考大纲》精心编写，具有以下特点： 标准性：试卷题型、题量、难度与正式考卷一致，并附最新考试真题及参考答案。 全面性：10套标准预测试卷，全面覆盖《大纲》规定考查的知识及能力，并突出重点。 预测性：每套试卷均由命题专家根据历年试题对命题规律进行总结和预测后，题题精选而成，命中率高。
对不起，这个没有。因为国家已经不公布自学考试的答案了。谢谢。
我明晰,严燕生,但愿说对了有｀｀
试题有，答案没有。国家并没有公布过自考的答案，网路中的答案都是网友自己从书上找来的，还有个不是办法的办法就是找前几年出的辅导书，后面一般都有前两年的试题和答案。
稍微用点心吧同学，连书都不想翻，你不想学没人会帮你。因为答案可能分布在书的任何一页，怎么可能就考那么几页呢是不
自己动脑筋,就会发现题目其实很简单,加油哦!相信你一定能行!~_~ *_*
网上是找不到的，就算找到有人提供也不一定正确，建议你到自考书店购买一考通，里面会有历年的试题及答案。祝你顺利！
你好，自考历次真题和答案可以网上看看有没有，一般自考辅导试卷有专门的历次考试试题的。自考书籍主要是教材、大纲和辅导书模拟题历次考试真题，可以网上试试，或是有卖那种历次考试真题的试卷的辅导资料的可以，或是模拟试题都是可以的。
函授教学主要以有计划、有组织、有指导的自学为主，并组织系统的集中面授，参加函授学习的学生平时以自学为主，面授时间一般为周末或者晚上集中面授7-10天左右，下学期开学后考试。那么，有专升本函授考试高等数学试题及答案吗？ 2023年成人高考专升本《高等数学二》模拟试卷及参考答案一 2023年成人高考专升本《高等数学二》模拟试卷及参考答案汇总 2023年成人高考专升本《高等数学二》模拟试卷及参考答案一 2023年成人高考专升本《高等数学二》模拟试卷及参考答案二 2023年成人高考专升本《高等数学二》模拟试卷及参考答案三 2023年成人高考专升本《高等数学二》模拟试卷及参考答案四 2023年成人高考专升本《高等数学二》模拟试卷及参考答案五自考/成考有疑问、不知道如何总结自考/成考考点内容、不清楚自考/成考报名当地政策，点击底部咨询官网，免费领取复习资料：
31 解决方案： FC = 14.3N/mm 2风云= 300N/mm 2 H0 = HC-8-20/2 = 600-25-8-10 =557毫米 X = Asfy /α1fcb= 1964×300 /（1.0×14.3×250）=165毫米<ξbh0= 0.55×557 =306毫米亩=α1fcbx（H0-X / 2）= 1.0×14.3×250×165×（557 - 二分之一百六十五）= 280KN·M> M = 240kN·m的见了。剪力设计值？ 32 解决方案： 1）V = 200KN 2），复合截面尺寸 HW = H0 = H-= 500 -35 =465毫米HW / B = 465/200 = 2.325 0.25βcfcbh0= 0.25×1.0×11.9×200×465 = 276.675kN> V = 200KN截面的尺寸，以满足 3）检查计算出来的配置是否箍筋因为V1 / V =??？二百分之一百八十零= 90％> 75％ 1.75 /（λ1）ftbh0 = 1.75 /（λ1）×1.27×200 ×465 = 206.692 /（箍筋数量计算λ+1）[你的主题是不给剪跨比λ的值，所以下面不能再继续计算，但以下计算的想法] /> 4） V = 1.75 /（λ+1）ftbh0 + FYV ASV / s的H0 nSv1 / S = 再求S = 最后检查的最小配筋率 BR /> 希望你能有所帮助。